Question 54180
The formula you need to use is {{{delta(L)=alpha*L1*delta(T)}}}
{{{delta(L)}}}=Length final(L2)- length initial(L1)
{{{delta(T)}}}=Temperature final(T2) - Temperature initial(T1)
{{{alpha}}} =  the coefficient of linear expansion
{{{delta(L)=5.006m-5.00m=.006m}}}
{{{delta(T)=48C-6C=42C}}}
L1=5.00m
{{{delta}}}=delta (I don't have a triangle delta, sorry)and {{{alpha}}}=alpha in greek
Solve the equation for alpha
{{{(delta(L))/L1(delta(T))=(alpha*L1*delta(T))/L1(delta(T))}}}
{{{delta(L)/L1*(delta(T))=alpha}}}
{{{.006m/(5.00m*42C)=alpha}}}
{{{2.857*10^-5/C=alpha}}}
{{{highlight(alpha=2.857*10^-5C^(-1))}}}
Happy Calculating!!!