Question 54273
INVESTING $ 18,750 AND OBTAINING $ 20,867 TOTAL FOR INTEREST FOR THE 10% & 12% INVESTMENTS.
WE HAVE $20,867-$18,750=$2,117. THUS THERE ARE TWO PARTS OF THE $18,750 BEING INVESTED X & ($18,750-X).
 
THUS THE INVESTMENTS ARE .12X+.10(18,750-X)=2,117 OR .12X+1,875-.10X=2,117 OR

.12X-.10X=2,117-1,875 OR .02X=242 OR X=242/.02 OR X=12,100 INVESTED @ 12% &

18,750-12,100=6,650 INVESTED @ 10%

PROOF .12*12,100+.10*6,650=2,117 OR 1,452+665=2,117 OR 2,117=2,117

& 18,750+2,117=20,867 OR 20,867=20,867