Question 564032
solve the equation...(q+2/3)+(q-4/4)=2
:
{{{(q+2)/3}}}+{{{(q-4)/4}}} = 2
:
Multiply by the Lowest common denominator,
12*{{{(q+2)/3}}} + 12*{{{(q-4)/4}}} = 12(2)
Cancel the denominators and you have
4(q+2) + 3(q-4) = 24
:
4q + 8 + 3q - 12 = 24
7q - 4 = 24
7q = 24 + 4
7q = 28
q = 28/7
q = 4
:
:
See if that works in the original problem
{{{(4+2)/3}}}+{{{(4-4)/4}}} = 2
{{{6/3}}}+{{{0/4}}} = 2
2 + 0 = 2