Question 563426
Note that


*[tex \LARGE \sigma = \sqrt{\frac{\sum_{i=1}^n (x_i - \mu)^2}{n}}]


and that variance is equal to the square of the standard deviation. The best method is simply to use a calculator to input the data values, and you should obtain


*[tex \LARGE \sigma \approx 15.19]


*[tex \LARGE \sigma^2 \approx 230.8]