Question 560710
Anything parallel to this line will have the same slope. So all we need to do is find the slope of the line that goes through these points.




Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-3,-10\right)]. So this means that {{{x[1]=-3}}} and {{{y[1]=-10}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-9,2\right)].  So this means that {{{x[2]=-9}}} and {{{y[2]=2}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(2--10)/(-9--3)}}} Plug in {{{y[2]=2}}}, {{{y[1]=-10}}}, {{{x[2]=-9}}}, and {{{x[1]=-3}}}



{{{m=(12)/(-9--3)}}} Subtract {{{-10}}} from {{{2}}} to get {{{12}}}



{{{m=(12)/(-6)}}} Subtract {{{-3}}} from {{{-9}}} to get {{{-6}}}



{{{m=-2}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-3,-10\right)] and *[Tex \LARGE \left(-9,2\right)] is {{{m=-2}}}




So therefore, any parallel line will also have a slope of -2.

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