Question 53397
Complete the ordered pairs so that each is a solution for the given equation.
3x+4y=12 

(0, ),
3*0+4Y=12.....Y=3
(0,3)

 ( ,3/4),
3X+4*3/4=12.......
3X=9
X=3
(3,3/4)

 ( ,0),
3X+4*0=12
X=4
(4,0)


 (8/3, ) 
3*8/3+4Y=12
4Y=12-8=4
Y=1
(8/3,1)


McGraw Hill 6th edition, chapter 6, section 1, problem # 24. Thanks for your help!!