Question 54063
6x^2+9y^2=36
Isolate the Y

9y^2 = 36- 6x^2
 y^2 = 36/9 - 6x^2/9
 y^2 = 4- 1/3x^2
 y   = {{{sqrt(4-(1/3)x^2)}}}


For X intercept y=0
 0  = {{{sqrt(4-(1/3)x^2)}}}
 0  = 4-1/3x^2
-4  = -1/3x^2
 X^2= -4/-1/3
    = 12
x   = {{{sqrt (12)}}}
    = +   3.464101615138         or     -   3.464101615138


For Y intercept x=0
Y= {{{sqrt(4-(1/3)0^2)}}}
 = {{{sqrt(4)}}}
 = +2 ( as U koe this is a functio there is only one Y itercept)




 {{{ graph( 300, 200, -6, 5, -10, 10, (4-(1/3)x^2)^(1/2) }}}