Question 557996
27 using the exponential from
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There is no "the exponential form", there are an infinite number of them.
{{{3^3 = 27}}} uses integers
{{{(1/3)^(-3) = 27}}} sort of uses integers
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{{{10^(log(27)) = 27}}} is another
{{{x^y = 27}}} has an infinite # of solutions.