Question 556477
An arrow is fired into the air with an initial velocity of 128 feet per second. The height in feet of the (T) seconds after it was shot into the air is given by the function h(x)=-16t^2+128t. Find the maximum height of the arrow.
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h(x)=-16t^2+128t. Find the maximum height of the arrow.
Maybe you mean h(t)
h(t)=-16t^2+128t
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The max is the vertex of the parabola.  It's on the line of symmetry.
LOS is t = -b/2a
t = -128/-32 = 4 seconds
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f(4) = -16*16 + 128*4
f(4) = 512 - 256 = 256 feet