Question 555584
what is the answer in the retional expression 6c raised to two minus 23c minus 4 all over c raised to two minus 6c plus 8? please show the solution.
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(6c^2 - 23c - 4)/(c^2 -6c + 8)
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Factor:(6c^2-24c+c-4) / [(c-4)(c-2)]
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= [(6c)(c-4)+(c-4)] / [(c-4)(c-2)]
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= [(c-4)(6c+1)] / [(c-4)(c-2)]
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Cancel the common (c-4) factors:
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= (6c+1)/(c-2)
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Cheers,
Stan H.
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