Question 555266
Please help solv.  A digital photgraph is 30 pixel longer than it is wide and has a total area of 4000 pixels. Find the dimensions of this photograph.
Let x = width (in pixels)
then
x+30 = length
.
x(x+30) = 4000
x^2+30x = 4000
x^2+30x-4000 = 0
(x+80)(x-50) = 0
x = {-80, 50}
throw out the negative solution leaving:
x = 50 pixels (width)
.
Length:
x+30 = 50+30 = 80 pixels
.
Dimensions:
50 by 80 pixels