Question 555189
<pre>

Here is the formula for multiplying a "3 down by 2 across" matrix 
by a "2 down by 3 across" matrix.  The matrix you get when you 
multiply twn matrices gets its "down dimension" from the first
matrix and its "across dimension" from the second matrix: 

{{{(matrix(3,2,

a,b,
c,d,
e,f))}}}·{{{( matrix(2,3,

g,h,i,
j,k,l))}}} = {{{(matrix(3,3,

ag+bj, ah+bk, ai+bl,
cg+dj, ch+dk, ci+dl,
eg+fj, eh+fk, ei+fl))}}}

Use that formula and you'll get this answer, which is "3 down by 3 across":

{{{(matrix(3,2,

3,1,
3,2,
4,3))}}}·{{{( matrix(2,3,

7,2,1,
6,8,-2))}}} = {{{(matrix(3,3,

27,14,1,33,22,-1,46,32,-2))}}}

Edwin</pre>