Question 1135
 By factoring x^2+x-6 = (x+3)(x-2)
 and by squaring x^2-4x+4 = (x-2)^2
 Wehave
 10/(x^2+x-6)+ 3x/(x^2-4x+4)
 = 10/[(x+3)(x-2)] + 3x/ (x-2)^2
 = [10(x-2) + 3x (x+3)]/ [(x+3)(x-2)^2]
 = (3x^2 + 19 x -20)/ [(x+3)(x-2)^2]