Question 543396
If I've read your problem correctly, it's this, correct?:
{{{((9x^2y/5))/((3xy^2/20))}}}
A few things will be helpful to note here:
{{{((a/x))/b=a/(x*b)}}} and {{{a/((b/x))=(a*x)/b}}}
We can take your 2 pieces and make them easier to work with:
{{{(9x^2y/5)=(1/5)(9x^2y)}}} and {{{3xy^2/20=(1/20)(3xy^2)}}}
That makes your problem
{{{((1/5)(9x^2y))/((1/20)(3xy^2))=20(9x^2y)/(5(3xy^2))=(20*9*x^2*y)/(5*3*x*y^2)=(4*3*x)/y=12x/y}}}
So you were very close, you just had an extra Y in there.