Question 536128
how do you write 5^x-7=9^-9x as a 10 logrithm finding the value of x. 
..
5^(x-7)=9^-9x
take log of both sides using exponent rule
(x-7) log5=-9xlog9
(x-7)/9x=-log9/log5
using calculator
(x-7)/9x=-1.3652
x-7=9x*-1.362=-12.2869x
x+12.2869x=7
13.2869x=7
x=7/13.2869≈.5268