Question 530170
y = 1/3x -3
.
x = 0, y = -3
.
y = 0, x = 9
.
With two points you can draw a line.
.
{{{ graph(500,500,-10,10,-10,10,1/3*x-3) }}}
.
The point (-3,4) is not on the line.
.
You could construct a perpendicular line that goes through (-3,4), but it is not clear what you need.
.
A perpendicular line will have the inverse reciprocal slope, which is -3.
.
y = -3x + b
.
Use the point to fine 'b'.
.
4 = -3(-33) + b
4 = 9 + b
b = -5
.
y = -3x -5
.
{{{ graph(500,500,-10,10,-10,10,1/3*x-3, -3*x-5) }}}