Question 528611
Heather returned from the bank with $375. She had one more $20 bill than she had $10 bills. The number of $5 bills she had was one less than triple the number of $10 bills. How many of each denomination did she have?
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Equations:
5f + 10t + 20w = 375
w = t+1
f = 3t-1
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Substitute for "w" and for "f" and solve for "t"
5(3t-1) + 10t + 20(t+1) = 375
15t-5+10t+20t+20 = 375
45t + 15 = 375
45t = 360
t = 8 (# of $10 bills)
w = t+1 = 9 (# of $20 bills)
f = 3t-1 = 23 (# of $5 bills)
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Cheers,
Stan H.
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