Question 52068
How much of the amount to be removed is antifreeze?
Call the amount to be removed and repaced with water
{{{w}}}
{{{.6w}}} of that is antifreeze
I started out with {{{.6*3.6 = 2.16}}} liters antifreeze
I'm losing {{{.6w}}} liters
{{{(2.16 - .6w) / 3.6 = .50}}}
{{{3.6*.50 = 2.16 - .6w}}}
{{{1.8 = 2.16 -.6w}}}
{{{.6w = 2.16 - 1.8}}}
{{{.6w = .36}}}
{{{w = .6}}} liters removed and replaced with water
check
How much water is there now?
{{{.40*3.6 = 1.44}}} liters was unaffected by what we did
{{{.6*.6 = .36}}} liters is the alcohol that was replaced with water
{{{1.44 + .36 = 1.8}}} liters of water now
How much antifreeze is there now?
{{{.60*3.6 - .60*.6}}} liters
{{{2.16 - .36}}} =
{{{1.8}}} liters antfreeze now
That's a 50-50 mixture as it should be