Question 517979
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Let *[tex \Large x] represent the first consecutive odd integer.  Then *[tex \Large x\ +\ 2] is the next one, and *[tex \Large x\ +\ 4] is the one after that.  The sum of the three is 51, so:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ +\ 2\ +\ x\ +\ 4\ =\ 51]

Solve for *[tex \Large x], then calculate *[tex \Large x\ +\ 2] and *[tex \Large x\ +\ 4]

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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