Question 509420
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The sum of the measures of the interior angles of any polygon is given in degrees by:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 180(n\ -\ 2)]

where *[tex \Large n] is either the number of interior angles or the number of sides.

Therefore, the measure, in degrees, of one interior angle of a regular polygon is given by:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{180(n\ -\ 2)}{n}]

Hence, for your problem:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{180(n\ -\ 2)}{n}\ =\ 179]

Solve for *[tex \Large n]

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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