Question 500220
{{{(4p^2-25)/(5-2p)}}}
:
the numerator is the difference of squares and will factor to
{{{((2p+5)(2p-5))/(5-2p)}}}
;
In the denominator factor out -1 and we have
{{{((2p+5)(2p-5))/-1(2p-5)}}}
;
now we can cancel (2p-5)
{{{((2p+5))/(-1)}}} = -(2p + 5)