Question 497269
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{2}(x\ +\ 4)\ =\ \frac{1}{3}(3x\ -\ 6)]


Let's start by getting rid of those pesky fractions.  Notice that we have a denominator of 2 on one side and a denominator of 3 on the other side.  2 times 3 is 6, so let's multiply the whole schmierkäse by 6.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3(x\ +\ 4)\ =\ 2(3x\ -\ 6)]


Now use the distributive property to get rid of the parentheses:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 12\ =\ 6x\ -\ 12]


Add -6x to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -3x\ +\ 12\ =\ -12]


Add -12 to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  -3x\ =\ -24]


Multiply both sides by *[tex \Large -\frac{1}{3}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 8]


One problem per post.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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