Question 492943
Distance(d) equals Rate (r) times Time (t) or d=rt; r=d/t and t=d/r

Let d=distance to her appointment
And t=time required to travel to her appointment
Then d=60t
On the return trip:
d=28(t+24/60)=28(t+2/5) (Lets deal in hours for the time being )
So our equation to solve is:
60t=28(t+2/5)
60t=28t+56/5
32t=56/5
160t=56
t=56/160=7/20 hr or 21 min
d=60t=60*7/20 =21 mi

CK
at 28 mph on the return trip, it would take her
21/28 = 3/4 hr or 45 min
45-21=24 min longer


Hope this helps---ptaylor