Question 490747


let the first part be {{{x}}},the second part is {{{y}}}, and the third part is {{{z}}}

given:

the first part is {{{3}}} less than the second part

{{{x+3=y}}}


the third part is {{{1/2}}} of the second part

{{{z=y/2}}}...or {{{z=(x+3)/2}}}

{{{x+y+z=72}}}

{{{x+(x+3)+(x+3)/2=72}}}.....solve for {{{x}}}

{{{2x+3+x/2+3/2=72}}}

{{{2.5x+4.5=72}}}

{{{2.5x=72-4.5}}}

{{{2.5x=67.5}}}

{{{x=67.5/2.5}}}

{{{highlight(x=27)}}}...the first part

now find the second part

{{{y=x+3}}}

{{{y=27+3}}}

{{{highlight(y=30)}}}

and the third part


{{{z=(x+3)/2}}}

{{{z=(27+3)/2}}}

{{{z=30/2}}}

{{{highlight(z=15)}}}


check:


{{{x+y+z=72}}}

{{{27+30+15=72}}}

{{{57+15=72}}}

{{{72=72}}}