Question 464546


{{{-78r^11/-3r^7}}}.......you are dividing two negative products and result will be positive

={{{78r^11/3r^7}}}....now both numerator and denominator divide by {{{3}}}

={{{cross(78)26r^11/cross(3)1r^7}}}

={{{26r^11/r^7}}}......now use exponent rule {{{a^x/a^y=a^(x-y)}}}

={{{26r^(11-7)}}}

={{{26r^4}}}..this is the quotient