Question 461815
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Your given equation is in standard form, so the slope of the line is the opposite of the coefficient on *[tex \Large x] divided by the coefficient on *[tex \Large y].

The slopes of perpendicular lines are negative reciprocals, that is:

*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]

So, calculate the slope of the given line and then take the negative reciprocal (turn the fraction over and change the sign) to find the slope of the desired line.

Now that you have the slope of the desired line and you are given a point on the desired line you can use the point-slope form to write your equation.

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]

where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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