Question 47659
f(x) = (3/2)^x
x = -2
f(x) = (3/2)^(-2) = 3^(-2)/2^(-2) = 2^2 / 3^2 = 4/9
(-2,4/9)
x = -1
f(x) = (3/2)^(-1) = 3^(-1)/2^(-1) = 2/3
(-1,2/3)
x = 0
f(x) = (3/2)^0 = 1
(0,1)
x = 1
f(x) = (3/2)^1 = 3/2
(1,3/2)
x = 2
f(x) = (3/2)^2 = 3^2 / 2^2 = 9/4
(2,9/4)
{{{graph(600,600,-10,10,-10,10,(3/2)^x)}}}