Question 456979
{{{1/(a-b) + 4/(b-a) - 8/(a+b) - (11a-5b)/(b^2-a^2)

= (-1)/(b-a) + 4/(b-a) - 8/(b+a) - (11a-5b)/(b^2-a^2)

= 3/(b-a) - 8/(b+a) - (11a-5b)/(b^2-a^2)

=(11a - 5b)/(b^2 - a^2) -  (11a-5b)/(b^2-a^2)

=0}}}