Question 46770
{{{A = Pe^(rt)}}}
{{{1700 = 1000e^(0.042t)}}}
{{{1.7 = e^(0.042t)}}}
{{{log(e,1.7) = log(e,e^(0.042t))}}}
{{{log(e,1.7) = 0.042t}}}
{{{log(e,1.7)/0.042 = t}}} About 12.6 so 13 years
d.)