Question 443609
take the ln of both sides.

{{{ln(e^(pi-x)) = ln(pi^(e-x))}}}
{{{pi -x = (e-x)*ln(pi)}}}
{{{pi - x = e*ln(pi)  - x*ln(pi)}}}
{{{pi - e*ln(pi) = x-x*ln(pi)}}}
{{{pi - e*ln(pi) = x(1-ln(pi))}}}
{{{highlight((pi-e*ln(pi))/(1-ln(pi))) = x}}}