Question 443261
Recognize that 4^2 = 16 and 4^3 = 64. Then:

{{{4^2^(2x+3) = 4^3^(x+2)}}}
Use the product rule:
{{{4^(2*(2x+3)) = 4^(3(x+2))}}}
{{{4^(4x+6) = 4^(3x+6)}}}
Take the log(base4) of both sides:
{{{ 4x+6 = 3x+6}}}
{{{highlight(x = 0)}}}