Question 440799
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Hi
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y = (x-4)^2+6
 1) parabola opens upward a = 1 > 0  Vertex Pt(4,6) is a minumum pt
 2) Line of symetry is the x = 4
 3) relative to the the translation form the origin: to the right 4 & up 6
{{{drawing(300,300, -10,10,-10,10,blue(line(4,10,4,-10))  ,    grid(1),
circle(4, 6,0.3),
graph( 300, 300, -10,10,-10,10, 0, (x-4)^2+6))}}}