Question 45804
THE TWO POINTS TO GRAPH THE PROBLEM ARE (100,102)(150,78) THUS THE SLOPE OF THE LINE IS (78-102)/(150-100) OR -24/50 OR -.48 THEN THE EQUATION FOR THIS LINE IS Y=-.48X+B NOW REPLACING Y & X BY ONE OF THE POINTS WE FIND THE VALUE OF B THUS 102=-.48*100+B OR 102=-48+B OR 102+48=B OR B=150 THUS THE EQUATION FOR THIS LINE/RELATIONSHIP IS Y=-.48X+150