<PRE><B>Question 437945</B>
Find the center and foci of the hyperbola.
(y+6)2 - (x-8)2
------    -----=1
   9        16

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h = 8; k = -6; a = 4 ; b = 3
Note: The hyperbola opens up and down
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c = sqrt(a^2+b^2) = sqrt(16+9) = 5

Center: (8,-6)
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Foci: (8,-6-5) and (8,-6+5)
that is: (8,-11) and (8,-1)
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Cheers,
Stan H.</PRE>