Question 436173
x^2+12x+20=0

x=1 y=32
x=-1y=9
x=2,y=48
x=-2,y=0
x=-10,y=0
x-12,y=20

{{{drawing(500,500,-50,50,-50,50,circle(1,32,1),circle(-1,9,1),circle(
2,48,1),circle(-2,0,1),circle(-10,0,1),circle(-12,20,1),graph(500,500,-50,50,-50,50,y=x^2+12x+20))}}}				
x^2+12x+20
x^2+10x+2x+20
x(x+10)+2(x+10)
(x+10)(x+2)