Question 433414
3,5 hyperbola center . length of transverse axis 14. give equation for that
<pre>
A hyperbola with a horizontal transverse axis of length 2a 
and center (h,k), and a conjugate axis of 2b has an equation 
of the form:

(x - h)ｲ   (y - k)ｲ
覧覧覧覧 - 覧覧覧覧  = 1
  aｲ          bｲ

A hyperbola with a vertical transverse axis of length 2a
and center (h,k), and a conjugate axis of 2b has an equation 
of the form:

(y - k)ｲ   (x - h)ｲ
覧覧覧覧 - 覧覧覧覧  = 1
  aｲ          bｲ
 
So what you gave is not enough information.  
"a" is half the transverse axis, so the equation could be

(x - 3)ｲ   (y - 5)ｲ
覧覧覧覧 - 覧覧覧覧  = 1
  7ｲ          bｲ

where b could be any number, or it could be

(y - 5)ｲ   (x - 3)ｲ
覧覧覧覧 - 覧覧覧覧  = 1
  7ｲ          bｲ

where b could be any number.  

Repost the problem, giving all the information.

Edwin</pre>