Question 45098
{{{3(n - 1)^2 + 20 = 19(n - 1)}}}
{{{3(n^2 - 2n + 1) + 20 = 19n - 19}}}
{{{3n^2 - 6n + 3 + 20 = 19n - 19}}}
{{{3n^2 - 25n + 42 = 0}}}
{{{3n^2 - 7n - 18n + 42 = 0}}}
{{{(3n^2 - 7n) + (-18n + 42) = 0}}}
{{{n(3n - 7) - 6(3n - 7) = 0}}}
{{{(n - 6)(3n - 7) = 0}}}
n = 6
and
n = 7/3