Question 428103
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That depends a great deal on how much of your function that follows the "/" is in the denominator of the rational part of the function, to wit:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Q_1(x)\ =\ x\ +\ \frac{8}{x^2}\ +\ 36x]


has a different domain than


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Q_2(x)\ =\ x\ +\ \frac{8}{x^2\ +\ 36x}]


and both have a different domain than:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Q_3(x)\ =\ x\ +\ \frac{8}{x^{2\ +\ 36x}}]


Repost your question using parentheses to eliminate ambiguities, that is either:


Q(x) = x + (8/x^2) + 36x


Q(x) = x + 8/(x^2 + 36x)


Q(x) = x + 8/x^(2 + 36x)


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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