Question 427041
How does a 4th grader find the dimensions of a rectangle when the perimeter is 58 and the area is 54.
---------------
Perimeter = 2L + 2W = 58 --> L + W = 29
Area = L*W = 54
------------------
L = 54/W
(54/W) + W = 29
54 + W^2 = 29W
{{{W^2 - 29W + 54 = 0}}}
(W - 2)*(W - 27) = 0
W = 2
L = 27
-----------
I'm not sure that'll work in the 4th grade, it's been awhile since I was there.
----------------------
Try this:
Factor 54 and look for a pair that adds to 29
54 = 
1 x 54
2 x 27
3 x 18
6 x 9

Only 2 by 27 fits.
If the solution is not integers, that won't work.