Question 423184
One number is 4/3 times another and they have a differce of 10. What are the two numbers?
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Equations:
x = (4/3)y
x-y = 10
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Substitute for "x" and solve for "y":
(4/3y)-y = 10
(1/3)y = 10
y = 30
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Now solve for "x":
x = (4/3)y
x = (4/3)30
x = 40
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Solution: (40,30)
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Cheers,
stan H.