Question 421337
The average price of a computer is $1,200 with a standard deviation of $220. Computer prices are normally distributed. 
a. What is the probability that a randomly selected computer will have a price of at least $1,530?
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z(1530) = (1530-1200)/220 = 1.5
P(x > 1530) = P(z > 1.5) = 0.0668
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b. Computers with prices of more than $1,750 receive a discouint. What is the percentage of computers will receive the discount?
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z(1750) = (1750-1200)/220 = 2.5
P(x > 1750) = P(z > 2.5) = 0.0062
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Cheers,
Stan H.