Question 420255
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Hi
write the first five terms of the sequence: substituting for n = 1 to 5
{{{a[n] = n +3}}}  {4,5,6,7,8...}
{{{a[n] = 3n^2}}}  {3,12,27,48,75...}
{{{a[n] = n^2+n+6}}} {8,11,16,23,32...}
{{{a[n] = 16-n^2}}}  {15,12,7,0,-9,...}