Question 416720
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The area between circle 2 and circle 1 is the area of circle 2 minus the area of circle 1.

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \pi(2x)^2\ -\ \pi x^2\ =\ 4x^2\pi\ -\ x^2\pi\ =\ 3x^2\pi]

The area between circle 4 and circle 3 is the area of circle 4 minus the area of circle 3.  Same deal as before.

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ B\ =\ \pi(4x)^2\ -\ \pi(3x)^2\ =\ 16x^2\pi\ -\ 9x^2\pi\ =\ 7x^2\pi]

So

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A:B\ =\ \frac{A}{B}\ =\ \frac{3x^2\pi}{7x^2\pi}\ =\ \frac{3}{7}]

John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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