Question 411023
  <pre><font size = 3 color = "indigo"><b>
Hi
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
log2 9+ log2 a = log2 13
log2 9+ log2 a - log2 13 = 0
log2 9a/13 = 0
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
  2^0= 9a/13
   1 = 9a/13
  13/9 = a