Question 409979
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Hi
Note:*[tex \LARGE\ \ log_bx + log_by = log_b(xy) ]
 log(x)+log(x)=2
 log(x^2)=2
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
  10^2 = x^2
    x = 10       |(Note: -10 is an Extraneous solution)

CHECKING our Answer***
 log 10 + log 10 = 1 + 1 = 2