Question 409018
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Hi
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
Write an equation of the straight line that is &#8869; to the line y=-5x + 8 
 y = (1/5)x + b  | &#8869; Lines have slopes that are negative reciprocals of one another, that is  -5*(1/5) = -1 
 y = (1/5)x + b  |using order pair Pt(12,0) to solve for
 0 = 12/5 + b
-12/5 = b
 y = (1/5)x -12/5  OR x-5y = 12 in standard form
Note m = 1/5: as y increases/decreases by 1, x increases/decreases by 5  
 
 {{{drawing(300,300,   -15,15,-15,15, grid(1),
circle(12,0,0.5),
circle(0, -2.4,0.5),
graph( 300, 300, -15,15,-15,15,0,.2x-12/5))}}}