Question 408018
I will walk you through with one. 

(6, -5) and is parallel to the line whose equation is 2x - 3y = 11?


2x - 3y = 11

add 3y to both sides
2x=11+3y
-11
2x-11=3y

3y=2x-11
/3
y= (2/3)*x-11/3

slope m = 2/3
The parallel line will have the same slope as that of the given line. 

so slope of the required line will be 2/3
.. 
line passes through (6,-5)
plug the value of slope , and the point (6,-5) to find b the y intercept
of the required line

y=mx+b
-5=2/3 *6+b
-5=4+b
b=-9
...
so the equation has slope 2/3 and y intercept -9
y=(2/3)x-9

...
CHECK
{{{graph(300,300,-10,10,-10,10,y=(2/3)x-11/3,y=(2/3)x-9)}}}