Question 407705
Note that all the x exponents (except for the 9) are odd, which means that {{{x^5 = -(-x)^5}}}. Since f(6) = 17, then f(6) - 9 = 8, and


{{{a*6^5 + b*6^3 + c*6 = 8}}}


Since the function is odd, then


{{{a*(-6)^5 + b*(-6)^3 + c*(-6) = -8}}}


Adding 9 to obtain the value of f(-6) we get f(-6) = 1.