Question 43578
{{{x + 2 - 2*sqrt(x+2) =0}}}
{{{x + 2 = 2*sqrt(x+2) }}}
{{{(1/2)x + 1 = sqrt(x+2) }}}
{{{((1/2)x + 1)^2 = x + 2 }}}
{{{(1/4)x^2 + x + 1 = x + 2 }}}
{{{(1/4)x^2 = 1 }}}
{{{x^2 = 4}}}
{{{x = 2}}} or {{{x = -2}}}
(A)