Question 394079
{{{x - y = 10}}}
{{{3x - 10 = 8y + 40}}}
x is the larger number in this case
so break down the second one, so you can line it up
{{{3x - 10 = 8y + 40}}}
{{{3x - 8y = 50}}}
{{{1x - 1y = 10}}}
multiply the second equation by -3, so you can cancel the X's
{{{-3x + 3y = -30}}}
{{{ 3x - 8y =  50}}}
add them up
{{{-5y = 20}}}
{{{y = -4}}}
now that you have y, just plug it into the original equation to get x
{{{x - y = 10}}}
{{{x - (-4) = 10}}}
{{{x + 4 = 10)}}}
{{{x = 6}}}
so the solution would be
(6,-4)